0.001=x^2+0.03x

Solution for 0.001=x^2+0.03x equation:

0.001=x^2+0.03x

We move all terms to the left:

0.001-(x^2+0.03x)=0

We get rid of parentheses

-x^2-0.03x+0.001=0

We add all the numbers together, and all the variables

-1x^2-0.03x+0.001=0

a = -1; b = -0.03; c = +0.001;
Δ = b2-4ac
Δ = -0.032-4·(-1)·0.001
Δ = 0.0049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.03)-\sqrt{0.0049}}{2*-1}=\frac{0.03-\sqrt{0.0049}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.03)+\sqrt{0.0049}}{2*-1}=\frac{0.03+\sqrt{0.0049}}{-2}
$